轉(zhuǎn)帖自http://www.yesky.com/20030407/1661941.shtml

如何確保在C#中只有一個(gè)程序(實(shí)例)運(yùn)行?

　　解答:主要應(yīng)用System.Diagnostics名字空間中的Process類來實(shí)現(xiàn),思路,我們在運(yùn)行程序前,查找進(jìn)程中是否有同名的進(jìn)程,同時(shí)運(yùn)行位置也相同程,如是沒有運(yùn)行該程序,如果有,就將同名的同位置的程序窗口置前.
主要代碼:


[C#]
public static Process RunningInstance()
{
Process current = Process.GetCurrentProcess();
Process[] processes = Process.GetProcessesByName (current.ProcessName);
//查找相同名稱的進(jìn)程
foreach (Process process in processes)
{
//忽略當(dāng)前進(jìn)程
if (process.Id != current.Id)
{
//確認(rèn)相同進(jìn)程的程序運(yùn)行位置是否一樣.
if (Assembly.GetExecutingAssembly().Location.Replace("/", "\\") == current.MainModule.FileName)
{
//Return the other process instance.
return process;
}
}
}
//No other instance was found, return null.
return null;
}