井字游戲用C語言編寫的源代碼: //程序5. 8井字游戲#include int main（void）{int player = 0;贏家= 0; int選擇= 0; unsigned int行= 0; unsigned int colume = 0;字符板[3] [3] = {{'1'，'2'，'3'}，{'4'，'5'，'6'}，{'7'，'8'，'9' }}; //主游戲循環. 只要沒有獲勝者printf（“這是一個井字游戲，請盡情享受！”），游戲將持續進行9圈. for（unsigned int i = 0; i <9 &&="" winner="=" 0;="" ++="" i）{//顯示白板printf（“="" \="" n”）;="" printf（“％c="" |％c="" |％c="" \="" n”，板[0]="" [0]，板[0]="" [1]，板[0]="" [2]）；="" printf（“="" ---="" +="" ---="" +="" ---="" \="" n”）;="" printf（“％c="" |％c="" |％c="" \="" n”，board="" [1]="" [0]，board="" [1]="" [1]，板[1]="" [2]）；="" printf（“="" ---="" +="" ---="" +="" ---="" \="" n”）;="" printf（“％c="" |％c="" |％c="" \="" n”，board="" [2]="" [0]，board="" [2]="" [1]，board="" [2]="" [2]）;玩家="i％2" +1;="" 獲取有效的玩家平方選擇{printf（“玩家％d，請輸入一個有效的平方數”“，將％c放置在哪里:="" ”玩家，（玩家="=" 1）？'x':="" 'o'）;="" scanf（“％d”，＆choice）;="" row="--choice" 3;="" colume="選擇％3;" }=""><0 ||選擇=""> 8 || board [row] [colume]>'9'）； //插入玩家symbleboard [row] [colume] =（player == 1）？'X': 'O'; //首先檢查對角線是否是對角線if（（board [0] [0] == board [1] [1] && board [0] [0] == board [2] [2]）||（ board [0] [2] == board [1] [1] && board [0] [2] == board [2] [0]））贏家=玩家；否則{//為（未簽名的int行= 0；行<= 2;="" ++行）{if（（board="" [line]="" [0]="=" board="" [line]="" [1]="" &&板[線]="" [0]="=板[線]" [2]）||（板[0]="" [線]="=板[1]" [線]="" &&板[0]="" [線]="=板[2]">winner = player;}}} //游戲結束，因此顯示最終的boardprintf（“ \ n”）; printf（“％c |％c |％c \ n”，board [0] [0 ]用c語言編寫游戲，板[0] [1]，板[0] [2]）； printf（“ --- + --- + --- \ n”）; printf（“％c |％c |％c \ n”，board [1] [0]，board [1] [1]， board [1] [2]）; printf（“ --- + --- + --- \ n”）; printf（“％c |％c |％c \ n”，board [2] [0]，board [2] [1]用c語言編寫游戲，board [2] [2]）; //顯示結果消息if（winner）printf（“ \ n恭喜，玩家％d，您是贏家！\ n”，贏家）; else printf（“ \ n太無聊了，是平局\ n”）;返回0; }

本文來自本站，轉載請注明本文網址：
http://www.pc-fly.com/a/jisuanjixue/article-248904-1.html